9701_s11_qp_41
A paper of Chemistry, 9701
Questions:
9
Year:
2011
Paper:
4
Variant:
1

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Taken together, nitrogen and oxygen make up 99% of the air. Oxygen is by far the more reactive of the two gases, and most of the substances that react with air combine with the oxygen rather than with the nitrogen. State one reason why the molecule of nitrogen, N2, is so unreactive. Despite the apparent lack of reactivity of N2, nitrogen atoms have been found to form bonds with almost all of the elements in the Periodic Table. Lithium metal reacts with nitrogen gas at room temperature to give lithium nitride, Li3N. Magnesium produces magnesium nitride, Mg3N2, as well as magnesium oxide, when heated in air. Calculate the lattice energy of magnesium nitride using the following data, in addition to relevant data from the Data Booklet. enthalpy change value/kJ mol–1 atomisation of Mg+148 total of electron affinities for the change NN3–+2148 enthalpy of formation of Mg3N2–461 lattice energy = kJ mol–1 For Examiner’s Use Lithium reacts readily with nitrogen, and because of this Li3N has been considered as a possible intermediate in the ‘fixing’ of nitrogen to make ammonia-based fertilisers. + Li + H2O N2Li3N NH3 + A Construct an equation for the reaction between Li3N and H2O, and hence identify compound A. Using your knowledge of the Haber process, consider one advantage and one disadvantage of using lithium as a means of fixing nitrogen, rather than the Haber process. advantage of the lithium method disadvantage of the lithium method Another possible advantage of Li3N is that it contains a large percentage by mass of nitrogen. Another fertiliser that contains a large percentage by mass of nitrogen is urea, NH2CONH2. Calculate and compare the percentages by mass of nitrogen in Li3N and NH2CONH2. What class of organic compound is urea? Write an equation for the production of ammonia by the reaction between urea and water. Urea can be applied directly to the soil either before or during the growing of crops. What would be a major disadvantage of using lithium nitride in this way?
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For Examiner’s Use The reaction producing tri-iodomethane can be used as a test for the presence of certain groups within a molecule. State the reagents and conditions used for this reaction. Write the structural formula of one functional group that would give a positive result with this iodoform reaction. What do you observe in a positive test? In the following table place a tick (✓) in the column against each compound that would give a positive result with this test, and a cross (✗) against each compound that would give a negative result. compound result CH3OH CH3CH2OH CH3CHO CH3CO2H CHO COCH3 For Examiner’s Use The iodoform test can be used, along with other reactions, to work out the structures of unknown compounds. Use the information in the table below to deduce the structures of the compounds in the following scheme, and draw these structures in the boxes provided. hot concentrated acidified KMnO4 C7H12O C3H6O + C4H6O3 D E F Results of tests (✓ indicates a positive result; ✗ indicates a negative result) test results of tests with each compound D E F iodoform ✗ ✓ ✓ Fehling’s solution ✓ ✗ ✗ 2,4-dinitrophenyl- hydrazine reagent ✓ ✓ ✓ Na2CO3✗ ✗ ✓ structures D(C7H12O) E(C3H6O) F(C4H6O3) Treatment of compound F with NaBH4 gives compound G, C4H8O3. Heating G with Al2O3 gives a mixture of three isomeric unsaturated carboxylic acids H, J and K, C4H6O2, two of which are stereoisomers of each other. Suggest structures for G, H, J, and K, and name the type of stereoisomerism shown. G Al2O3 H + J + K type of stereoisomerism
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For Examiner’s Use Chromatography is an important analytical technique in chemistry. There is a number of techniques under the general heading of chromatography. Paper and gas chromatography rely on partition to separate the components in a mixture, whereas thin-layer chromatography uses adsorption. Explain what is meant by partition and adsorption, in the context of chromatography. partition adsorption In paper or thin-layer chromatography, better separation may be achieved by running the chromatogram in one solvent, then turning the paper at right angles and running it in a second solvent. The chromatogram below was produced in this way. X solvent 2 sample applied here solvent 1 Ring the spot which was insoluble in solvent 1. Label as A and B the spots which were not resolved using solvent 1. For Examiner’s Use The mass spectrum shown was obtained from a compound of formula CpHqX, where X represents a halogen atom. relative intensity 100 110 120 130 m / e R Deduce the identity of X, giving a reason. X is If the relative heights of the M and M+1 peaks are 9 and 0.3 respectively, calculate the value of p. Use this value and the m / e value of the molecular ion to calculate the value of q, and hence the molecular formula of the compound. Show your working. Suggest a formula for the ion responsible for the peak labelled R. In the fragmentation of alcohols which occurs in a mass spectrometer, small stable, neutral molecules are sometimes produced. Suggest the identity of two such molecules, each with an Mr less than 30.
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