9701_s20_qp_43
A paper of Chemistry, 9701
Questions:
10
Year:
2020
Paper:
4
Variant:
3
Login to start this paper & get access to powerful tools
1
An aqueous solution of cobalt(contains the [Co(H2O)6]2+ complex ion. Define the term complex ion. Samples of [Co(H2O)6]2+ are reacted separately with aqueous sodiumhydroxide and with an excess of aqueous ammonia. Give the following information about these reactions. ● ● the reaction of [Co(H2O)6]2+ with aqueous sodiumhydroxide colour and state of the cobalt-containing species ionic equation type of reaction ● ● the reaction of [Co(H2O)6]2+ with an excess of aqueous ammonia colour and state of the cobalt-containing species ionic equation type of reaction  When concentrated hydrochloricacid is added to a solution containing [Co(H2O)6]2+, a blue solution of [CoCl 4]2– is formed and the following equilibrium is established. [Co(H2O)6]2+ + 4Cl – [CoCl 4]2– + 6H2O Use Le Chatelier’s principle to suggest the expected observations when silvernitrate solution is added dropwise to the blue solution of [CoCl 4]2–. Explain your answer. The [Co(NH3)3Cl 3] complex shows stereoisomerism. Complete the three-dimensional diagrams to show the two isomers of [Co(NH3)3Cl 3]. Suggest the type of stereoisomerism. Co Co type of stereoisomerism  CompoundX, C6H18N4, is a tetradentate ligand. H2N NH2 N H X H N Suggest why one molecule of X can form four dative bonds. C6H18N4 reacts with aqueous cobalt(ions, [Co(H2O)6]2+, in a 1 : 1 ratio to form a new complex ion. Construct an equation for this reaction. 
11. Group 17  →  11.3. Some reactions of the halide ions
17. Carbonyl compounds  →  17.1. Aldehydes and ketones
11. Group 17  →  11.4. The reactions of chlorine
Open
3
The overall reaction for photosynthesis is shown. 6CO2 + 6H2O → C6H12O6 + 6O2 Water is oxidised in this process according to the following half-equation. 2H2O → O2 + 4H+ + 4e– half-equation 1 Use these equations to deduce the half-equation for the reduction of carbondioxide in this process.  Draw a fully labelled diagram of the apparatus that should be used to measure the standard electrode potential, E o, of O2in half-equation1 under standard conditions. Include all necessary chemicals.  For the cell drawn in , use the Data Booklet to calculate the and deduce which electrode is positive.  = V  identity of the positive electrode =  
11. Group 17  →  11.4. The reactions of chlorine
6. Electrochemistry  →  6.1. Redox processes: electron transfer and changes in oxidation number (oxidation state)
Open
4
The molecular formulae of three nitrogen‑containing compounds are given. S C6H5CONH2 T C6H5NH2 U C6H5CH2NH2 Describe and explain the relative basicities of S, T and U. > > most basic least basic  CompoundU can be prepared by two different methods as shown. NH2 NH2 Br O U reaction 1 reaction 2 Suggest reagents and conditions for reaction1 and for reaction2. reaction 1 reaction 2  State the type of reaction in reaction1 and name the mechanism in reaction2. type of reaction in reaction1 mechanism of reaction2  
12. Nitrogen and sulfur  →  12.1. Nitrogen and sulfur
13. An introduction to AS Level organic chemistry  →  13.1. Formulas, functional groups and the naming of organic compounds
Open
5
Benzene reacts with bromine in the presence of an aluminiumbromide catalyst, Al Br3, to form bromobenzene. This is a substitution reaction. No addition reaction takes place. Explain why no addition reaction takes place. Al Br3 reacts with bromine to generate an electrophile, Br+. Draw the mechanism of the reaction between benzene and Br+ ions. Include all relevant arrows and charges.  Write an equation to show how the Al Br3 catalyst is reformed. Suggest why bromination of phenol occurs more readily than bromination of benzene. There are four different carbocations with the same formula, C4H9 +. One structure is given in the table. Suggest the structural formulae of the three other carbocations. structure 1 CH3CH2CH2CH2 + structure 2 structure 3 structure 4  Benzene reacts with each of these carbocations in separate Friedel-Crafts alkylation reactions. In each reaction an organic compound with formula C10H14 is formed. The number of peaks observed in the carbon‑13 NMR spectrum of each compound is given. Suggest the structures for the three other compounds. number of peaks in carbon-13 NMR = 8 number of peaks in carbon-13 NMR = 6 number of peaks in carbon-13 NMR = 7 number of peaks in carbon-13 NMR = 8  
15. Halogen compounds  →  15.1. Halogenoalkanes
14. Hydrocarbons  →  14.2. Alkenes
Open
6
Compare and explain the relative acidities of 2‑chloropropanoicacid, 3‑chloropropanoicacid, and propanoicacid. Explain your answer. > > most acidic least acidic explanation  The numerical values of Ka for methanoic acid, HCO2H, and pyruvicacid, CH3COCO2H, are given. acid Ka HCO2H 1.78 × 10–4 CH3COCO2H 4.07 × 10–3 An equilibrium mixture containing the two acid-base pairs is formed. HCO2 – + CH3COCO2H HCO2H + CH3COCO2 – Use the Ka values to calculate the equilibrium constant, Keq, for this equilibrium.  Keq = Use your value of Keq to predict the position of this equilibrium. Indicate this by placing a tick () in the appropriate box in the table. Explain your answer. equilibrium lies to the left equilibrium lies in the middle equilibrium lies to the right  Ethanedioic acid, HO2CCO2H, has two dissociation constants, Ka1 and Ka2, whose pKa values are 1.23 and 4.19. Suggest equations to show the two dissociations that give rise to these pKa values. pKa1 1.23 pKa2 4.19  State the mathematical relationship between pKa and the acid dissociation constant Ka. Three tests were carried out on separate samples of the organic acids shown in the table. The following results were obtained. = observed change = no observed reaction test reagentand conditions HCO2H CH3COCO2H HO2CCO2H observed change          Complete the table with the reagentand conditions and the observed change for each test. Assume these organic acids all have a similar acid strength. A sample of pyruvicacid, CH3COCO2H, is analysed by carbon‑13 NMR spectroscopy. Three peaks are observed. Complete the table by: ● ● circling the carbon atom responsible for the chemical shift ● ● stating the hybridisation of the circled carbon atom. chemical shift (δ) carbon atom responsible for chemical shift hybridisation of the circled carbon atom O O C C O H H H C H O O C C O H H H C H O O C C O H H H C H  An ester of pyruvicacid, F, is dissolved in CDCl 3 and analysed by proton NMR spectroscopy. C C H3C O F O CH2 O CH3 The proton NMR spectrum of F is shown. δ / ppm Use the proton NMR spectrum of F to complete the table. chemical shift (δ) group responsible for the peak splitting pattern number of 1H atoms responsible for the peak 1.3 2.2 4.0  Deuterium oxide, D2O, where D is 2H, can be used as a solvent in proton NMR spectroscopy. The proton NMR spectrum of alanine in CDCl 3 has 4 peaks. The proton NMR spectrum of alanine in D2O has 2 peaks. H3C C NH2 H alanine COOH On the diagram of alanine, circle the protons that show peaks in both NMR spectra. Explain your answer. The ionic product, Kw, for D2O has a value of 1.35×10–15 mol2 dm–6 at 298 K. Write the expression for the Kw of D2O. Kw =  Calculate the pH of pure, neutral D2O at 298 K. Assume [D+] is equivalent to [H+] for pH calculations.  pH = 
7. Equilibria  →  7.2. Brønsted–Lowry theory of acids and bases
Open
7
Silver carbonate, Ag2CO3, is sparingly soluble in water. The numerical value of the solubility product, Ksp, for silver carbonate is 6.3×10–12 at 25 °C. Write an expression for the solubility product, Ksp, of Ag2CO3, and state its units. Ksp =  units =  Calculate the equilibrium concentration of Ag+ in a saturated solution of Ag2CO3 at 25 °C.  [Ag+] = mol dm–3 Solid Ag2CO3 is stirred at 25 °C with 0.050 mol dm–3 AgNO3 until no more Ag2CO3 dissolves. Calculate the concentration of carbonate ions, [CO3 2–], in this solution.  [CO3 2–] = mol dm–3 An electrochemical cell is set up to measure the electrode potential, E, for the Ag+ / Ag half‑cell using the saturated Ag2CO3with a standard hydrogen electrode. Use the Data Booklet, your answer to , and the Nernst equation to calculate the electrode potential, E, for this Ag+ / Ag half-cell.  E for Ag+ / Ag half-cell = V Silverchloride, AgCl, is sparingly soluble in water. The equation for the enthalpy change of solution is shown. AgCl → Ag++ Cl –= +65.5 kJ mol–1 Standard entropies are shown in the table. species AgCl Ag+Cl –S o / J K–1 mol–1 +96.2 +72.7 +56.5 Calculate the standard entropy change of solution, ∆S o.  ∆S o = J K–1 mol–1 Explain, with the aid of a calculation, why AgCl is insoluble in water at 25 °C. You should use data from this question and your answer to . 
7. Equilibria  →  7.1. Chemical equilibria: reversible reactions, dynamic equilibrium
11. Group 17  →  11.3. Some reactions of the halide ions
Open
8
Explain what is meant by the term buffer solution. Write an expression for the acid dissociation constant, Ka, for ammonium ions, NH4 +. Ka =  Write two equations to describe how a solution containing ammonium ions, NH4 +, and ammonia, NH3, can act as a buffer. The numerical value of Ka for NH4 +is 5.6×10–10 at 298 K. A buffer solution was prepared by adding 0.80 dm3 of 0.25 mol dm–3 ammonia, an excess, to 0.20 dm3 of 0.20 mol dm–3 hydrochloricacid. Calculate the pH of the buffer solution formed at 298 K.  pH = 
7. Equilibria  →  7.2. Brønsted–Lowry theory of acids and bases
12. Nitrogen and sulfur  →  12.1. Nitrogen and sulfur
Open
9
Manganese(oxide, MnO2, catalyses the decomposition of hydrogenperoxide, H2O2, as shown. MnO2 2H2O22H2O+ O2The mechanism involves the formation of the intermediate species, Mn2+, in the first step which is subsequently used up in the second step. State and use relevant electrode potentials, E o, to construct two equations to show how MnO2 can catalyse this reaction. equation 1 equation 2  The equation for the decomposition of hydrogen peroxide without a catalyst is shown. 2H2O2→ 2H2O+ O2Under certain conditions this reaction is found to be first order with respect to hydrogenperoxide, with a rate constant, k, of 2.0×10–6 s–1 at 298 K. Calculate the initial rate of decomposition of a 0.75 mol dm–3 hydrogenperoxide solution at 298 K.  initial rate = mol dm–3 s–1 A four-step mechanism is suggested for the reaction between hydrogen peroxide and iodide ions in an acidic solution. step 1 H2O2 + I– → IO– + H2O step 2 H+ + IO– → HIO step 3 HIO + I– → I2 + OH– step 4 OH– + H+ → H2O Step 1 is the rate-determining step. State what is meant by the term rate-determining step. Use this mechanism to construct a balanced equation for this reaction. Deduce the order of reaction with respect to each of the following. H2O2 = I– = H+ =  
11. Group 17  →  11.4. The reactions of chlorine
6. Electrochemistry  →  6.1. Redox processes: electron transfer and changes in oxidation number (oxidation state)
Open
10
The electronic configuration of transition element Q is [Ar] 3d2 4s2. Predict the likely oxidation states of elementQ in compounds. Suggest why transition elements often show variable oxidation states in their compounds, but typical s‑block elements such as calcium do not. Many enzymes contain transition element complexes. Describe, with the aid of a suitably labelled diagram, how an enzyme catalyses the breakdown of a substrate molecule. 
6. Electrochemistry  →  6.1. Redox processes: electron transfer and changes in oxidation number (oxidation state)
Open