0620_w12_qp_31
A paper of Chemistry, 0620
Questions:
7
Year:
2012
Paper:
3
Variant:
1

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For Examiner’s Use Both strontium and sulfur have chlorides of the type XCl 2. The table below compares some of their properties. strontium chloride sulfur chloride appearance white crystals red liquid formula SrCl 2 SCl 2 melting point / °C –120 boiling point / °C conductivity of liquid good poor solubility in water dissolves to form a neutral solution reacts to form a solution of pH 1 Use the data in the table to explain why sulfur chloride is a liquid at room temperature, 25 °C. Strontium is a metal and sulfur is a non-metal. Explain why both have chlorides of the type XCl 2. The electron distribution of a strontium atom is 2 + 8 + 18 + 8 + 2. Deduce the name of the acidic compound formed when sulfur chloride reacts with water. Explain the difference in the electrical conductivity of liquid strontium chloride and liquid sulfur chloride. For Examiner’s Use Strontium chloride-6-water can be made from the insoluble compound, strontium carbonate, by the following reactions. SrCO3+ 2HCl → SrCl 2+ CO2+ H2OSrCl 2 + 6H2O→ SrCl 2.6H2OThe following method was used to prepare the crystals. Add excess strontium carbonate to hot hydrochloric acid. Filter the resulting mixture. Partially evaporate the filtrate and allow to cool. Filter off the crystals of SrCl 2.6H2O. Dry the crystals between filter papers. How would you know when excess strontium carbonate had been added in step 1? Why is it necessary to fi lter the mixture in step 2? In step 3, why partially evaporate the fi ltrate rather than evaporate to dryness? In the above experiment, 50.0 cm3 of hydrochloric acid of concentration 2.0 mol / dm3 was used. 6.4 g of SrCl 2.6H2O was made. Calculate the percentage yield. number of moles of HCl used = number of moles of SrCl 2.6H2O which could be formed = mass of one mole of SrCl 2.6H2O is 267 g theoretical yield of SrCl 2.6H2O = g percentage yield = %