5054_w14_qp_21
A paper of Physics, 5054
Questions:
11
Year:
2014
Paper:
2
Variant:
1

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A student makes a 2.0 V battery by connecting two cells of electromotive force (e.m.f.) 2.0 V in parallel. The battery, an ammeter with different ranges and three different resistors are used to set up the circuit shown in . A 2.0 1 2.0 V 2.0 V 3.0 1 X Explain what is meant by electromotive force. State one advantage of using two cells in parallel rather than using a single 2.0 V cell. Resistor X and the 3.0 Ω resistor have a combined resistance that is equal to 2.0 Ω. Calculate the total resistance of the circuit, total resistance = the resistance of X. resistance of X = Determine the reading of the ammeter. reading = Suggest a suitable range for the ammeter. The current in the 2.0 Ω resistor is I2. The current in the 3.0 Ω resistor is I3. The current in X is IX. State the equation that relates I2, I3 and IX. State the potential difference (p.d.) across the 2.0 Ω resistor, p.d. = the 3.0 Ω resistor. p.d. = Question 11 continues on page 18. The student sets up a second circuit using a variable d.c. power supply, an ammeter and a 12 V metal filament lamp. The circuit is shown in Fig. 11. 2. A + d.c. power supply metal filament lamp – The d.c. power supply is set to 12 V and the ammeter reading is 1.5 A. The student changes the e.m.f. of the d.c. power supply to 6.0 V. The lamp dims and the ammeter reading changes. State and explain what happens to the resistance of the metal filament of the lamp. State whether the new ammeter reading is less than, equal to or greater than 0.75 A.