5054_w20_qp_21
A paper of Physics, 5054
Questions:
10
Year:
2020
Paper:
2
Variant:
1

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The density of water in a lake is 1000 kg / m3. At a depth of 25 m beneath the surface of the lake, the total pressure is 3.5 × 105 Pa. State what is meant by pressure. The gravitational field strength is 10 N / kg. Determine: the pressure due to 25 m of water pressure = the atmospheric pressure. atmospheric pressure = An underwater depth gauge contains a small cylinder as shown in . Gas is trapped inside the cylinder by a piston. The piston is free to move. outer face of piston piston gas The outer face of the piston is in contact with the water. As the depth gauge is lowered into the water, the piston moves into the cylinder. This moves a needle on a dial to indicate the depth of the gauge in the water. Explain why the piston moves into the cylinder. The temperature of the gas does not change as the piston moves into the cylinder. Explain, in terms of molecules, what happens to the pressure of the trapped gas as the piston moves into the cylinder. At the surface of the water, the volume of the trapped gas in the depth gauge is V0. On , sketch a graph to show how the volume of trapped gas decreases as the gauge is lowered into the water. V0 volume depth The instructions for the depth gauge state that, each time it is used, the needle of the dial must be re-set to zero at the surface of the water. Suggest one reason for this. The density of the air trapped in the depth gauge increases. The density of the water remains constant. Explain, in terms of the molecules of the water, why the density of the water remains constant.
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shows a wire of length l and cross-sectional area A. l A State how the resistance of the wire in depends on: l A. The cross-sectional area of a piece of metal wire is 7.5 × 10–4 cm2. The resistance of a 1.0 m length of the same wire is 6.4 Ω. The wire is made from metal W. shows a solid cube of side 1.0 cm. It is also made from metal W. 1.0 cm 1.0 cm 1.0 cm A B Calculate the resistance between the two opposite faces A and B of the cube. resistance = The wire in part is taped to a metre rule. shows that a 1.0 m length of the wire (resistance 6.4 Ω) is connected in series with a switch, a cell of electromotive force (e.m.f.) 1.2 V and a resistor of resistance 9.6 Ω. P 0 cm wire 1.2 V 9.6 Ω The switch is closed. Explain what is meant by electromotive force (e.m.f.). Calculate the potential difference (p.d.) across the 1.0 m length of the wire. p.d. = One input terminal of an oscilloscope is connected to the wire at point P, the 0 cm mark of the metre rule. The other terminal of the oscilloscope is connected to a sliding contact. Initially, this contact touches the wire at point P. The Y-gain setting on the oscilloscope is 0.20 V / cm. shows the screen of the oscilloscope with a horizontal trace across the middle of the screen. 1.0 cm 1.0 cm trace The sliding contact is slowly moved along the wire until it reaches the other end of the metre rule. Describe and explain what happens to the trace on the screen. A second, identical 1.2 V cell is connected in parallel with the cell in the circuit in . State one advantage of using two cells in parallel rather than a single cell. State and explain the effect on the trace in of adding the second cell in parallel.