2.1. Equations of motion
A subsection of Physics, 9702, through 2. Kinematics
Listing 10 of 285 questions
A trolley A moves along a horizontal surface at a constant velocity towards another trolley B which is moving at a lower constant speed in the same direction. shows the trolleys at time t = 0. horizontal surface A B Table 3.1 shows data for the trolleys. Table 3.1 trolley mass / kg initial speed / m s–1 A 0.25 0.48 B 0.75 0.12 The two trolleys collide elastically and then separate. Resistive forces are negligible. shows the variation with time t of the velocity v for trolley B. –0.1 –0.2 –0.3 –0.4 –0.5 0.1 0.1 0.2 0.3 0.4 0.5 0.2 0.3 0.4 0.5t / s v / m s–1 B State what is represented by the area under a velocity–time graph. Use Table 3.1 and to determine: the acceleration of trolley B during the collision acceleration of B = m s–2 the magnitude and direction of the final velocity of trolley A. magnitude = m s–1 direction On , sketch the variation of the velocity of trolley A with time t from t = 0 to t = 0.50 s.
9702_w23_qp_21
THEORY
2023
Paper 2, Variant 1
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Define acceleration. A ball is kicked from horizontal ground towards the top of a vertical wall, as shown in . 28° path of ball ball wall horizontal ground v 24 m (not to scale) The horizontal distance between the initial position of the ball and the base of the wall is 24 m. The ball is kicked with an initial velocity v at an angle of 28° to the horizontal. The ball hits the top of the wall after a time of 1.5 s. Air resistance may be assumed to be negligible. Calculate the initial horizontal component vX of the velocity of the ball. vX = m s−1 Show that the initial vertical component vY of the velocity of the ball is 8.5 m s−1. Calculate the time taken for the ball to reach its maximum height above the ground. time = s The ball is kicked at time t = 0. On , sketch the variation with time t of the vertical component vY of the velocity of the ball until it hits the wall. It may be assumed that velocity is positive when in the upwards direction. 0 0 5.0 –5.0 –10.0 10.0 0.2 0.4 0.6 0.8 1.0 1.2 1.4 1.6 t / s vY / m s–1 Use the information in to determine the maximum height of the ball above the ground. maximum height = m The maximum gravitational potential energy of the ball above the ground is 22 J. Calculate the mass of the ball. mass = kg A ball of greater mass is kicked with the same velocity as the ball in . State and explain the effect, if any, of the increased mass on the maximum height reached by the ball. Air resistance is still assumed to be negligible.
9702_m16_qp_22
THEORY
2016
Paper 2, Variant 2
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Questions Discovered
285