2. Kinematics
A section of Physics, 9702
Listing 10 of 285 questions
Explain what is meant by a scalar quantity and by a vector quantity. scalar: vector: A ball leaves point P at the top of a cliff with a horizontal velocity of 15 m s–1, as shown in . cliff 25 m 15 m s–1 ball path of ball Q P ground The height of the cliff is 25 m. The ball hits the ground at point Q. Air resistance is negligible. Calculate the vertical velocity of the ball just before it makes impact with the ground at Q. vertical velocity = m s–1 Show that the time taken for the ball to fall to the ground is 2.3 s. Calculate the magnitude of the displacement of the ball at point Q from point P. displacement = m Explain why the distance travelled by the ball is different from the magnitude of the displacement of the ball.
9702_s14_qp_23
THEORY
2014
Paper 2, Variant 3
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Define speed and velocity and use these definitions to explain why one of these quantities is a scalar and the other is a vector. speed: velocity: A ball is released from rest and falls vertically. The ball hits the ground and rebounds vertically, as shown in . ground initial position ball rebound The variation with time t of the velocity v of the ball is shown in . 4.0 2.0 6.0 8.0 10.0 12.0 0 0 1.0 2.0 3.0 – 4.0 – 8.0 – 2.0 – 10.0 – 6.0 t / s v / m s–1 Air resistance is negligible. Without calculation, use to describe the variation with time t of the velocity of the ball from t = 0 to t = 2.1 s. Calculate the acceleration of the ball after it rebounds from the ground. Show your working. acceleration = m s–2 Calculate, for the ball, from t = 0 to t = 2.1 s, 1. the distance moved, distance = m 2. the displacement from the initial position. displacement = m On , sketch the variation with t of the speed of the ball. 4.0 2.0 6.0 8.0 10.0 12.0 0 0 1.0 2.0 3.0 – 4.0 – 8.0 – 2.0 – 10.0 – 6.0 t / s speed / m s–1
9702_s15_qp_21
THEORY
2015
Paper 2, Variant 1
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A stone is thrown vertically upwards. The variation with time t of the displacement s of the stone is shown in . 1.0 s t / s 2.0 3.0 Use to describe, without calculation, the speed of the stone from t = 0 to t = 3.0 s. Assume air resistance is negligible and therefore the stone has constant acceleration. Calculate, for the stone, the speed at 3.0 s, speed = m s−1 the distance travelled from t = 0 to t = 3.0 s, distance = m the displacement from t = 0 to t = 3.0 s. displacement = m direction On , draw the variation with time t of the velocity v of the stone from t = 0 to t = 3.0 s. 1.0 v / m s–1 t / s 2.0 3.0
9702_s15_qp_22
THEORY
2015
Paper 2, Variant 2
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Questions Discovered
285