7.3. Preparation of salts
A subsection of Chemistry, 0620, through 7. Acids, bases and salts
Listing 10 of 150 questions
The soluble salt hydrated lithium sulfate is made by titration from the soluble base lithium hydroxide. burette filled with sulfuric acid aqueous lithium hydroxide and a few drops of a pH indicator conical flask The sulfuric acid is added slowly from the burette until the indicator just changes colour. The volume of sulfuric acid needed to just neutralise the lithium hydroxide is noted. Describe how you would continue the experiment to obtain pure dry crystals of hydrated lithium sulfate. Using 25.0 cm3 of aqueous lithium hydroxide, concentration 2.48 mol / dm3, 2.20 g of hydrated lithium sulfate was obtained. Calculate the percentage yield, giving your answer to one decimal place. 2LiOH + H2SO4 → Li2SO4 + 2H2O Li2SO4 + H2O → Li2SO4.H2O Number of moles of LiOH used = Number of moles of Li2SO4.H2O which could be formed = Mass of one mole of Li2SO4.H2O = 128 g Maximum yield of Li2SO4.H2O = g Percentage yield = % An experiment was carried out to show that the formula of the hydrated salt is Li2SO4.H2O. A sample of the hydrated salt was weighed and its mass recorded. It was then heated and the anhydrous salt was weighed. This procedure was repeated until two consecutive masses were the same. This procedure is called ‘heating to constant mass’. What is the reason for heating to constant mass? The mass of the hydrated salt is m1 and the mass of the anhydrous salt is m2. Explain how you could show that the hydrated salt has one mole of water of crystallisation per mole of the anhydrous salt.
0620_s14_qp_32
THEORY
2014
Paper 3, Variant 2
Questions Discovered
150