1.5.3. Centre of gravity
A subsection of Physics, 0625, through 1. Motion, forces and energy
Listing 10 of 59 questions
shows a mobile bird sculpture that has been created by an artist. 12 cm 30 cm pivot tail bird sculpture M E hole in sculpture for pivot M is the centre of mass of the bird sculpture, including its tail (but not including the counter-weight that will be added later). The mass of the bird and tail is 1.5 kg. The bird sculpture is placed on a pivot. The artist adds the counter-weight at the end E of the tail so that the bird remains stationary in the position shown. Calculate the mass of the counter-weight. mass = The centre of mass of the sculpture with counter-weight is at the pivot. Calculate the upward force acting at the pivot. force = The sculpture is rotated clockwise to the position shown in . It is held still, then carefully released. pivot counter-weight M State whether the sculpture will stay in that position, rotate further clockwise or rotate back anticlockwise. Explain your answer to .
0625_s12_qp_32
THEORY
2012
Paper 3, Variant 2
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shows a mobile bird sculpture that has been created by an artist. 12 cm 30 cm pivot tail bird sculpture M E hole in sculpture for pivot M is the centre of mass of the bird sculpture, including its tail (but not including the counter-weight that will be added later). The mass of the bird and tail is 1.5 kg. The bird sculpture is placed on a pivot. The artist adds the counter-weight at the end E of the tail so that the bird remains stationary in the position shown. Calculate the mass of the counter-weight. mass = The centre of mass of the sculpture with counter-weight is at the pivot. Calculate the upward force acting at the pivot. force = The sculpture is rotated clockwise to the position shown in . It is held still, then carefully released. pivot counter-weight M State whether the sculpture will stay in that position, rotate further clockwise or rotate back anticlockwise. Explain your answer to .
0625_s12_qp_33
THEORY
2012
Paper 3, Variant 3
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A metre rule balances when the 50 cm mark is directly above a pivot. State where in the rule its centre of mass is located. shows an apple and a 0.40 N weight placed on the rule so that the rule remains balanced at the 50 cm mark. 25 cm 45 cm pivot 50 cm mark apple 0.40 N weight (not to scale) The centre of mass of the apple is 25 cm from the pivot and the centre of mass of the weight is 45 cm from the pivot. Calculate the weight of the apple, weight = the mass of the apple. mass = The apple is not moved. The weight is removed from the rule and the pivot is moved to the left until the rule balances as shown in . pivot 50 cm mark apple (not to scale) Explain why the arrangement in balances. The pivot in is closer to the 50 cm mark than to the centre of mass of the apple. Compare the weight of the rule to the weight of the apple.
0625_s14_qp_33
THEORY
2014
Paper 3, Variant 3
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Questions Discovered
59