9700_w19_qp_23
A paper of Biology, 9700
Questions:
6
Year:
2019
Paper:
2
Variant:
3
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1
is a diagram of a molecule of haemoglobin. A Name the structure labelled A on . State the function of structure A. Haemoglobin is described as a globular protein. Explain why this protein is described as globular. The gene HBB codes for the β-globin polypeptide. State why a polypeptide, such as β-globin, is described as a polymer. A single base change in the DNA of the gene HBB results in a change to the amino acid sequence of β-globin. In the sequence, a single glutamic acid is replaced by valine. Outline the effects of this change in the amino acid sequence of β-globin on the structure and function of a haemoglobin molecule. Haemoglobin interacts with carbon dioxide and carbon monoxide. Outline the role of haemoglobin in the transport of carbon dioxide.
2. Biological molecules  →  2.3. Proteins
8. Transport in mammals  →  8.2. Transport of oxygen and carbon dioxide
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2
Meristematic tissue is found in the growing region of plants, such as root tips. shows a section through the meristematic region of a root tip of onion, Allium cepa. H G F E magnification ×2200 D C B A Table 2.1 shows the numbers of cells in different stages of the cell cycle that were observed in sections of the meristematic regions of root tips of A. cepa. Table 2.1 stage of cell cycle one example of cell from number of cells counted in each stage replicate 1 replicate 2 replicate 3 mean interphase prophase metaphase anaphase telophase total Complete Table 2.1 by using the letters A to H from to identify one cell in each stage of the cell cycle. The total length of time taken for meristematic cells of A. cepa to complete one cell cycle at 25 °C is 12 hours. Using sections similar to the one in , the length of time spent in each stage of the cell cycle can be estimated. To obtain the estimate, the percentage of cells in that stage is calculated. Using the data in Table 2.1, calculate: • the percentage of cells in anaphase • the mean length of time in minutes for anaphase. Show your working. percentage of cells in anaphase = % mean length of time in anaphase = min State one event that occurs during cytokinesis in the cell cycle of plant cells, such as those shown in .
5. The mitotic cell cycle  →  5.2. Chromosome behaviour in mitosis
16. Inheritance  →  16.1. Passage of information from parents to offspring
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3
The tomato plant, Solanum lycopersicum, does not tolerate periods of drought (water shortage). Researchers have produced a tomato plant that has an improved tolerance of drought. The researchers measured the width and the length of open stomata in plants that are tolerant of drought and tomato plants that are not tolerant. is the formula used to calculate the size of an open stoma (stomatal aperture). stomatal aperture = width of open stoma length of open stoma shows the mean stomatal aperture of the two groups of tomato plants. shows the rates of transpiration of the two groups of tomato plants when kept in identical conditions of drought. 0.00 0.05 0.10 0.15 0.20 0.25 0.30 0.35 0.40 0.00 0.50 1.00 1.50 2.00 2.50 3.00 3.50 drought tolerant mean stomatal aperture transpiration rate / mmol water m–2s–1 non-drought tolerant drought tolerant non-drought tolerant The nuclei of plants produce small lengths of RNA known as microRNAs. MicroRNAs in guard cells have been shown to prevent the synthesis of some proteins. The guard cells of the drought-tolerant tomato plants produced more microRNA molecules than the guard cells of the non-tolerant plants. MicroRNA molecules do not prevent transcription but interact with messenger RNA (mRNA). Suggest how this microRNA can interact with mRNA to prevent the production of proteins in guard cells of S. lycopersicum.
14. Homeostasis  →  14.2. Homeostasis in plants
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4
In mammals, arteries branch to form smaller blood vessels called arterioles. Arterioles branch to form capillaries that supply blood to tissues. Explain the ways in which the structure of an artery is adapted to its function. shows transmission electron micrographs of cross-sections through an arteriole and a capillary. lumen arteriole capillary magnification ×2000 magnification ×6500 lumen Identify the cells inside the lumen of the arteriole in and state one reason for your identification. Describe the differences between the arteriole and the capillary that are visible in . shows a capillary network in a mammalian tissue. The arrows indicate the direction of flow of body fluids. artery X arteriole capillaries not to scale Capillaries have a role in the formation of tissue fluid. Explain how tissue fluid is formed in the capillary network. The vessels labelled X in carry excess tissue fluid back into the circulatory system. Name the fluid inside the vessels labelled X and state one way in which its composition differs from blood plasma. name of fluid difference
8. Transport in mammals  →  8.1. The circulatory system
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5
Influenza is an infectious disease caused by the influenza A virus. This virus causes influenza in birds and mammals. is a diagram of an influenza A virus. Haemagglutinin allows the virus to attach to host cells by binding to receptors on the cell surface membrane of the host cells. Neuraminidase is an enzyme that helps the virus to leave host cells after the virus has replicated. 100 nm haemagglutinin neuraminidase State two features of all viruses that are visible in . Neuraminidase removes parts of the host cell receptors that bind to haemagglutinin. This helps newly-formed viruses to leave host cells. Drugs have been developed to act on neuraminidase. These drugs prevent viruses from leaving host cells. Suggest and explain how these drugs act to prevent viruses leaving cells. The human immune system produces antibodies in response to the presence of antigens, such as neuraminidase and haemagglutinin. Outline the events that occur during an immune response leading to the production of antibodies against an antigen, such as haemagglutinin. Researchers are developing methods to produce antibodies to give artificial passive immunity to influenza. Suggest the advantages and disadvantages of artificial passive immunity. State two ways in which mammals can acquire natural passive immunity to infectious diseases, such as influenza.
11. Immunity  →  11.2. Antibodies and vaccination
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6
is a diagram of the cell surface membrane of a squamous epithelial cell lining an alveolus. R A B S A student measured the line A–B and calculated the actual width of the membrane in . State the unit that the student should use for the actual width of the membrane. With reference to , state how to identify the external surface of the cell surface membrane. Name R and S in and describe their roles in the membrane. component R name role component S name role
4. Cell membranes and transport  →  4.1. Fluid mosaic membranes
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