16.3. Gene control
A subsection of Biology, 9700, through 16. Inheritance
Listing 8 of 8 questions
Yeast cells respond to changes in glucose concentration in their environment by using transcription factors to switch off genes. When glucose is present: • Mig1 transcription factors bind to the promoters of five genes • Mig1 binding to the promoters stops transcription of these genes. The genes that are repressed by Mig1 code for five enzymes that allow yeast cells to metabolise the sugar galactose when glucose is absent. Complete Table 5.1 to show three chemical differences between a transcription factor, such as Mig1, and a promoter. Table 5.1 transcription factor promoter difference 1 difference 2 difference 3 Mig1 binds to promoter sites with these features: • 17 base pairs long • includes a region of five repeating adenine-thymine pairs • includes a region of six repeating cytosine-guanine pairs. Promoter sites to which Mig1 binds are known as Mig1-binding promoter sites. Bioinformatic techniques were used to analyse the yeast genome to look for sections of DNA that match these features. The information obtained for four chromosomes is shown in Table 5.2. Table 5.2 yeast chromosome chromosome size / base pairs number of Mig1-binding promoter sites per chromosome A 230 018 B 813 184 C 316 620 D 1 531 933 Explain why bioinformatic techniques were used to obtain the information in Table 5.2. Identify, with a reason, the yeast cell chromosome that is most likely to include genes that code for enzymes that metabolise galactose. Mig1 binds to 27 promoters on these four chromosomes. Yeast cells also have other chromosomes where Mig1 binds to additional promoters. Five different enzymes, coded by five genes, must be made for yeast cells to metabolise galactose. Suggest reasons why an individual diploid yeast cell has a larger number of Mig1-binding promoter sites than the expected number of ten. The repression of genes involved in galactose metabolism in yeast is similar to events at the lac operon in the bacterium Escherichia coli. Explain how E. coli represses the production of proteins needed to metabolise lactose sugar.
9700_s20_qp_42
THEORY
2020
Paper 4, Variant 2
The lac operon of prokaryotes contains a group of structural genes that are under the same control and are transcribed together. Another operon found in prokaryotes is the trp operon. summarises the structure and control of the trp operon. trpR promoter operator attenuator (regulates the extent of transcription) structural genes are transcribed RNA polymerase binds to promoter inactive repressor active repressor tryptophan trpE trpD trpC trpB trpA trpR promoter operator attenuator no transcription of structural genes trpE trpD trpC trpB trpA Describe the differences in structure and control between the lac operon and the trp operon. Suggest why structural genes in operons are transcribed together. trpA is an example of a structural gene and trpR is an example of a regulatory gene. Describe the differences between the functions of structural genes and regulatory genes. trpA codes for the enzyme tryptophan synthase. Tryptophan synthase catalyses the formation of the amino acid tryptophan. Explain why tryptophan synthase is an example of a repressible enzyme. Control of gene expression in eukaryotes is more complex than in prokaryotes. In plants, the control of gene expression can involve plant hormones, such as gibberellin, and proteins known as JAZ and MYC. Describe how gibberellin activates genes in plant cells. Transcription of some plant genes is prevented when JAZ proteins bind to other proteins known as MYC. When JAZ proteins are broken down, MYC proteins are free to bind to DNA. This allows transcription to begin. State the term that is used to describe proteins such as MYC proteins.
9700_w22_qp_42
THEORY
2022
Paper 4, Variant 2
Questions Discovered
8