16. Inheritance
A section of Biology, 9700
Listing 10 of 199 questions
In the sweet pea plant, Lathyrus odoratus, one gene codes for flower colour and one gene codes for pollen grain shape. Flower colour is either purple or red. Pollen grain shape is either long or round. The inheritance of these genes is an example of autosomal linkage. • The allele F for purple flowers is dominant over the allele f for red flowers. • The allele G for long pollen grains is dominant over allele g for round pollen grains. Explain the meaning of the term autosomal linkage. A dihybrid cross was carried out between homozygous dominant and homozygous recessive sweet pea plant parents to produce the F1 generation. The offspring from the F1 generation were crossed to produce the F2 generation. Draw a genetic diagram to show a dihybrid cross between two offspring from the F1 generation. Assume that these genes are closely linked and that there are no crossing over events. The actual results of the dihybrid cross are shown in Table 2.1. Table 2.1 phenotypes of F2 offspring number of individuals purple flowers, long pollen grains purple flowers, round pollen grains red flowers, long pollen grains red flowers, round pollen grains State how the results support the fact that this is an example of autosomal linkage. In a test cross, an individual of known genotype is crossed with an individual that has a dominant phenotype but unknown genotype. State the genotype of the known individual in a test cross. A test cross was carried out with sweet pea plants known to be heterozygous for both flower colour and pollen grain shape. The results of the test cross are shown in Table 2.2. Table 2.2 phenotypes of offspring of test cross number of individuals purple flowers, long pollen grains purple flowers, round pollen grains red flowers, long pollen grains red flowers, round pollen grains The result of a test cross can be used to determine a crossover value (CO. A crossover value is the percentage of the total number of offspring showing recombination. The crossover value (COcan be calculated using the formula shown in . COV = number of recombinants total number of individuals # 100 Calculate the COV from the results shown in Table 2.2. COV = % Suggest what information about the relative distance between the linked genes can be gained from crossover values.
9700_s18_qp_42
THEORY
2018
Paper 4, Variant 2
The tiger barb, Puntigrus tetrazona, is a South American fish that is popular worldwide as an aquarium fish. shows the appearance of a normal (wild-type) tiger barb. • Tiger barbs that show a wild-type phenotype are gold with black stripes. • Tiger barbs that show an albino phenotype are gold with white stripes. • In 2012, a fish breeder discovered a tiger barb with a new, transparent, phenotype. This fish had a transparent body and black stripes. The fish breeder crossed the tiger barb showing the new transparent phenotype with a tiger barb showing the albino phenotype. All the F1 offspring were wild-type. These F1 offspring were crossed with each other. Table 6.1 shows the phenotypes obtained in the F2 generation and the number of fish showing each phenotype. Table 6.1 F2 phenotype number of fish wild-type (gold with black stripes) albino (gold with white stripes) transparent with black stripes transparent with white stripes The fish breeder concluded that the new transparent phenotype had occurred because of a mutation. Explain how the results in Table 6.1 support this conclusion. State the approximate whole-number ratio shown by the results in Table 6.1. Explain what the results in Table 6.1 show about the genes and alleles that determine the wild-type, albino and the two different transparent phenotypes in tiger barbs. The F1 tiger barbs all looked the same but the F2 offspring showed variation. The F2 offspring showed four different phenotypes. Describe the processes that occurred during meiosis in the F1 fish that allowed this variation to occur.
9700_w23_qp_41
THEORY
2023
Paper 4, Variant 1
The tiger barb, Puntigrus tetrazona, is a South American fish that is popular worldwide as an aquarium fish. shows the appearance of a normal (wild-type) tiger barb. • Tiger barbs that show a wild-type phenotype are gold with black stripes. • Tiger barbs that show an albino phenotype are gold with white stripes. • In 2012, a fish breeder discovered a tiger barb with a new, transparent, phenotype. This fish had a transparent body and black stripes. The fish breeder crossed the tiger barb showing the new transparent phenotype with a tiger barb showing the albino phenotype. All the F1 offspring were wild-type. These F1 offspring were crossed with each other. Table 6.1 shows the phenotypes obtained in the F2 generation and the number of fish showing each phenotype. Table 6.1 F2 phenotype number of fish wild-type (gold with black stripes) albino (gold with white stripes) transparent with black stripes transparent with white stripes The fish breeder concluded that the new transparent phenotype had occurred because of a mutation. Explain how the results in Table 6.1 support this conclusion. State the approximate whole-number ratio shown by the results in Table 6.1. Explain what the results in Table 6.1 show about the genes and alleles that determine the wild-type, albino and the two different transparent phenotypes in tiger barbs. The F1 tiger barbs all looked the same but the F2 offspring showed variation. The F2 offspring showed four different phenotypes. Describe the processes that occurred during meiosis in the F1 fish that allowed this variation to occur.
9700_w23_qp_43
THEORY
2023
Paper 4, Variant 3
Questions Discovered
199