14. Hydrocarbons
A section of Chemistry, 9701
Listing 10 of 313 questions
Use Electrophoresis can be used to separate amino acids which are produced by the hydrolysis of a polypeptide. Using glycine as an example, explain why the result of electrophoresis depends on pH. The diagram below shows the results of electrophoresis in neutral solution. At the start of the experiment a spot of a solution containing a mixture of amino acids P, Q, R and S was placed in the middle of the plate. Following electrophoresis the amino acids had moved to the positions shown in the lower diagram. before + – after + – P Q R S Which amino acid existed mainly as a zwitterion in the buffer solution? Explain your answer. Assuming amino acids R and S carry the same charge when in this buffer solution, which is likely to be the larger molecule? Explain your answer. Amino acids may also be separated by using two-dimensional paper chromatography. This involves putting a spot of the mixture on the corner of a piece of chromatography paper and allowing a solvent to soak up the paper. The paper is then dried, turned through 90° and placed in a second solvent. This method gives better separation than a one solvent method. Paper chromatography relies on partition between the solvent applied and another phase. What is this second phase? Examiner’s Use The table below shows the Rf values for some amino acids in two different solvents. amino acid Rf solvent 1 Rf solvent 2 A 0.1 0.2 B 0.0 0.4 C 0.3 0.0 D 0.8 0.9 E 0.6 0.5 Use the grid below to plot the positions of the amino acids after two-dimensional paper chromatography using solvent 1 followed by solvent 2. solvent 2 solvent 1 solvent front solvent front spot applied here Which amino acid travelled fastest in both solvents? Which amino acid did not move at all in solvent 2?
9701_s07_qp_4
THEORY
2007
Paper 4, Variant 0
Although standard electrode potentials are measured for solutions where the concentrations of ions are 1.0 mol dm–3, cells used as sources of battery power tend to operate with more concentrated solutions. This question concerns the electrode reactions involved in the hydrogen-oxygen fuel cell and the lead-acid car battery. In the hydrogen-oxygen fuel cell, H2and O2are fed onto two inert electrodes dipping into NaOH. V hydrogen oxygen NaOHThe following reactions take place. left hand electrode : H2+ 2OH–2H2O+ 2e– right hand electrode : O2+ 2H2O+ 4e– 4OH–Use the Data Booklet to calculate E o–– cell for this reaction. Construct an equation for the overall reaction. By using one of the phrases more positive, more negative or no change, deduce the effect of increasing [OH–] on the electrode potential of • the left hand electrode • the right hand electrode Hence deduce whether the overall Ecell is likely to increase, decrease or remain the same, when [OH–] increases. Explain your answer. Suggest one other reason why a high is used in the fuel cell. In the cells of a lead-acid car battery the following reactions take place. cathode: PbPb2++ 2e– anode: PbO2+ 4H++ 2e– Pb2++ 2H2OUse the Data Booklet to calculate E o–– cell for this reaction. Construct an equation for the overall reaction. The electrolyte in a lead-acid cell is H2SO4. Most of the Pb2+ions that are produced at the electrodes are precipitated as the highly insoluble PbSO4. Construct an equation for the overall cell reaction in the presence of H2SO4. By considering the effect of decreasing [Pb2+] on the electrode potentials of the cathode and the anode, deduce the effect of the presence of H2SO4in the electrolyte on the overall Ecell. State whether the Ecell will increase, decrease or remain the same. Overall Ecell will . Explain your answer.
9701_s10_qp_41
THEORY
2010
Paper 4, Variant 1
Questions Discovered
313