7.1. Chemical equilibria: reversible reactions, dynamic equilibrium
A subsection of Chemistry, 9701, through 7. Equilibria
Listing 10 of 211 questions
Ethanoic acid can be reacted with alcohols to form esters, an equilibrium mixture being formed. CH3CO2H + ROH CH3CO2R + H2O The reaction is usually carried out in the presence of an acid catalyst. Write an expression for the equilibrium constant, Kc, for this reaction, clearly stating the units. Kc = units In an experiment to determine Kc a student placed together in a conical flask 0.10 mol of ethanoic acid, 0.10 mol of an alcohol ROH, and 0.005 mol of hydrogen chloride catalyst. The flask was sealed and kept at 25 °C for seven days. After this time, the student titrated all of the contents of the flask with 2.00 mol dm–3 NaOH using phenolphthalein indicator. At the end-point, 22.5 cm3 of NaOH had been used. Calculate the amount, in moles, of NaOH used in the titration. What amount, in moles, of this NaOH reacted with the hydrogen chloride? Write a balanced equation for the reaction between ethanoic acid and NaOH. Hence calculate the amount, in moles, of NaOH that reacted with the ethanoic acid. Use your results from to calculate the amount, in moles, of ethanoic acid present at equilibrium. Hence complete the table below. CH3CO2H ROH CH3CO2R H2O initial amount / mol 0.10 0.10 equilibrium amount / mol Use your results to calculate a value for Kc for this reaction. Esters are hydrolysed by sodium hydroxide. During the titration, sodium hydroxide reacts with ethanoic acid and the hydrogen chloride, but not with the ester. Suggest a reason for this. What would be the effect, if any, on the amount of ester present if all of the water were removed from the flask and the flask kept for a further week at 25 °C? Explain your answer.
9701_s11_qp_22
THEORY
2011
Paper 2, Variant 2
Questions Discovered
211