9701_s14_qp_43
A paper of Chemistry, 9701
Questions:
8
Year:
2014
Paper:
4
Variant:
3

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The ions of transition elements form complexes by reacting with ligands. State what is meant by the terms: complex, ligand. Two of the complexes formed by copper are [Cu(H2O)6]2+ and CuCl 4 2–. Draw three-dimensional diagrams of their structures in the boxes and name their shapes. [Cu(H2O)6]2+ shape: CuCl 4 2– shape: Platinum forms square-planar complexes, in which all four ligands lie in the same plane as the Pt atom. There are two isomeric complexes with the formula Pt(NH3)2Cl 2. Suggest the structures of the two isomers, and, by comparison with a similar type of isomerism in organic chemistry, suggest the type of isomerism shown here. Structures of isomers: isomer 1 isomer 2 Type of isomerism: Copper forms two series of compounds, one containing copper(ions and the other containing copper(ions. Complete the electronic structures of these ions. Cu([Ar] Cu([Ar] Use these electronic structures to explain why copper(salts are usually coloured, copper(salts are usually white or colourless. Copper(oxide and copper(oxide can both be used in the ceramic industry to give blue, green or red tints to glasses, glazes and enamels. The table lists the values for some compounds. compound / kJ mol–1 Cu2O–168.6 CuO–157.3 Cu(NO3)2–302.9 NO2+33.2 Copper(oxide can be produced in a pure form by heating copper(nitrate. Use suitable values from the table to calculate the H o for this reaction. Cu(NO3)2 CuO+ 2NO2+ 2 1 O2H o = kJ mol–1 Copper(oxide can be produced from copper(oxide. ● Use suitable values from the table to calculate H o for the reaction. 2CuOCu2O+ 2 1 O2H o = kJ mol–1 ● Hence suggest whether a low or a high temperature of oxidation would favour the production of copper(oxide. Explain your reasoning.
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Piperine is the compound responsible for the hot taste of black pepper. O N O O piperine Piperine is an amide and can be broken down as follows: O N HN O O piperine O OH + O O piperic acid piperidine Suggest reagents and conditions for this reaction. How many stereoisomers are there with the same structural formula as piperic acid (including piperic acid itself)? Draw the skeletal structure of a stereoisomer of piperic acid, different to the one shown above. Suggest structures for the compounds that would be formed when piperic acid is treated with an excess of hot concentrated acidifi ed KMnO4. Write the expression for Kw. Use your expression and the value of Kw in the Data Booklet to calculate the pH of 0.150 mol dm–3 NaOH. The pH of a 0.150 mol dm–3 solution of piperidine is 11.9. HN piperidine Suggest why this answer differs from your answer in . How would you expect the basicity of piperidine to compare to that of ammonia? Explain your reasoning. 20.0 cm3 of 0.100 mol dm–3 HCl was slowly added to a 10.0 cm3 sample of 0.150 mol dm–3 piperidine. The pH was measured throughout the addition. Calculate the number of moles of HCl remaining at the end of the addition. moles of HCl = Hence calculate the [H+] and the pH at the end of the addition. pH = On the following axes, sketch how the pH will change during the addition of a total of 20.0 cm3 of 0.100 mol dm–3 HCl. Mark clearly where the end point occurs. volume HCl added / cm3 pH From the following list of indicators, put a tick in the box by the side of the indicator most suitable for this titration. indicator pH at which colour changes place one tick only in this column A 0 - 1 B 3 - 4 C 11 - 12 D 13 - 14
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